10x^2+9x=15

Solution for 10x^2+9x=15 equation:

10x^2+9x=15

We move all terms to the left:

10x^2+9x-(15)=0

a = 10; b = 9; c = -15;
Δ = b2-4ac
Δ = 92-4·10·(-15)
Δ = 681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{681}}{2*10}=\frac{-9-\sqrt{681}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{681}}{2*10}=\frac{-9+\sqrt{681}}{20}
$